There is a limit to how much halite can dissolve in a liter of water. In the Binary Saturation Diagrams chapter this limit, the saturated solution composition, was found to be about 25 weight percent NaCl, 75 weight percent H2O at 21°C. What would happen if the water had KCl in it as well as NaCl? It turns out that a brine with KCl in it will hold less NaCl per gram of H2O at saturation than an H2O-NaCl-only brine. And the higher the KCl wt% in the solution, the lower the NaCl wt% will be in the halite-saturated solution. To show this graphically, we need to plot both weight percent NaCl and weight percent KCl along with weight percent H2O. A ternary (three-component) composition diagram is needed.
Figure 6.01. H2O-NaCl-KCl Diagram. Ternary phase diagram for the system H2O-NaCl-KCl at 20°C and 0.1 MPa pressure based on data from Gevantman (1971, Fig. 2.4). Click on the diagram to see an enlarged version for more information.
If halite is added to a halite-saturated brine, the halite will not dissolve. Instead, the proportion of halite to brine will increase. The two-phase brine + halite region (shaded green) of the diagram is filled with example tie lines, each of which connects the composition of halite to a saturated brine. The weight percent of crystals (Hl) to brine can be determined for each bulk composition using the lever rule. A similar two-phase brine + sylvite region (also shaded green) exists for sylvite-saturated liquids.
If enough sylvite is dissolved in a halite-saturated brine, the brine may become saturated with both sylvite and halite. If enough halite is dissolved in a sylvite-saturated brine, the brine may become saturated with both sylvite and halite. At equilibrium, all bulk compositions in the pink-shaded region are saturated with both halite and sylvite. The proportions of halite, sylvite, and brine for compositions in the pink, three-phase region may be detemined graphically using the ternary lever rule.